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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: if a+b+c+d=8 and abcd=4, then find a+b
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umang (229)

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???

Umang
    
ayshwarya (241)

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shud v find d max of a+b umang oooooooh umang plz come on 2 d online 4 a+b 2 b max its value is 6 4 it 2 b min its 2 if its rite i may tell u d procedure
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ayshwarya (241)

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rate me if im rite i may know my level of educason by ur votes
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umang (229)

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i just cant understanmd what u hav written !
pls explain clearly !!!
thanks !

Umang
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hash_include (381)

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i dont think the qsn is complete
take
a= 6 b =3 c= -(1/3) d = -(2/3)
both eqns will satisfy.. so a+b can have more than 1 value..

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eistien (343)

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yeah hash includee is rite you just have 2 equations and four unknowns  a+b can take many values is there any other restricting condition plz check up!!!
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umang (229)

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ok !
i agree with u both !
the question is wrong !!!
there might be a printing mistake in the book !
i i get it, i'll post it here !
thanks !!!

Umang
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sboosy (3009)

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\mbox{I think the question should have been as follows} \\ \\ a+b+c+d = 8 \ , abcd = 16 \ ,a+b=? \\ \\ \mbox{Now} \ \frac{a+b+c+d}{4} >= (abcd)^\frac{1}{4} \\ \\ \mbox{Here equality occurs....thus the numbers should be equal} \\ \\ a=b=c=d=2 \ \Longrightarrow a+b = 4
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umang (229)

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perfect !
thanks !!!

Umang
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santosh05 (279)

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a+b
------>[2 ] ab
  2 

similarly
(c+d)/2 >(cd)1/2

multiply both equations n u ll get d result..........

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