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Algebra

Blazing goIITian

Joined:	6 Jun 2009
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4 Jul 2009 18:23:40 IST

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let there be a complex no.Z and X be its conjugate. K=modulus of X^2 divided by Z X then.

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let there be a complex no.Z and X be its conjugate.K=modulus of X^2 divided by Z X then... modulus of K will be.....plz...give a detailed answer

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Comments (4)

venkat

Cool goIITian

Joined: 30 Nov 2008

Posts: 49

4 Jul 2009 18:29:18 IST

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Let X=a+ib. so Z=a-ib(because Z and X are conjugate to each other)

K=lX^2l/ZX

now try and get the answer.

if are not getting ask me then i will post the solution.

please reply me.

aal izz well

Blazing goIITian

Joined: 6 Jun 2009

Posts: 409

4 Jul 2009 18:31:34 IST

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no its not modulus of X square but... modulus of X raise to the power two...

Anirudh Kumar

Scorching goIITian

Joined: 25 Jan 2009

Posts: 246

5 Jul 2009 08:32:06 IST

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let Z = a +ib X = a-ib

|x|² = ZX

=> K = 1

Bipin Dubey

Forum Expert

Joined: 23 Jan 2007

Posts: 7942

5 Jul 2009 09:31:14 IST

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let Z=a+ib, then X = a-ib

$k=\frac{|X|^{2}}{ZX}$

$k=\frac{\left( \sqrt[]{a^{2}+b^{2}}\right)^{2}}{(a+ib)(a-ib)}$

$k=\frac{a^{2}+b^{2}}{a^{2}-i^{2}b^{2}}$

$k=\frac{a^{2}+b^{2}}{a^{2}+b^{2}}=1$

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