IIT JEE , AIEEE Forum - Mathematics , Algebra

sinjan.j

please see te pic in the following link and solve my question

please solve it fast guys.....!!!

sinjan.j

someone solve it please....!!!!

nadeemoidu

I dont know what 's the use of substituting u,v,w.
but u can do it like this
let x^logy=a
=> logy logx= log a ( taking log on both sides and using the formula log x^n=nlogx)
=> logx logy=log a
=> y^logx =a

therefore x ^logy= y^{log x} now substitute x^logy-logz as x^logy / x^logz ...
=x ^logy / z^logx
similarly doing like this to other terms, all will get cut and u get 1.

srujana

Hey nadeemoidu s method is perfectly right.......but if u want the q in the same way (using u, v, w) then do it this way

log_xu = log y-log x

log_yv = log z-log y

log_xw = log x-log y

log u=logx(logy-logz) ...............1

log v=logy(logz-logx) ...............2

logw=(logz(logx-logy) ...............3

adding 1 , 2&3

logu+logv+logw =0

log uvw=0

uvw = 1

nivedh_89

Hey sinjan................i just saw ur nudge but i thk ur dbt must hav been cleared !!!!!!

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