IIT JEE , AIEEE Forum - Mathematics , Algebra

learner

Solve

sq.rt(x²- 7x + 10) + 9 log₄(x/8) >= 2x + sq.rt.(14x - 20 - 2x²) - 13

Answer is x=2...

Kindly give solution or hints..

Rates assured!

Thanks! :-)

ayshwarya

hey frnd der r no proves nowadays check weder it satisfies d equation or not c dont think dat im unfit to solve even if u solv & get d ans u may ve to check it so y to wate time so check it

aditi_g

c for the 2 equations under the sqrt u know the expression under the root>=0 to have real solutn...

for the one on LHS domain is (0-infinity,2]U[5,infinity)

and on RHS its [2,5]

so for these 2 equations to be simultaneously satisfied either

x=2 or x=5

but if u put x=5 LHS <RHS

hence x=2

i hope u have understood...........

netkid07

*edited...

Aatish

Well I feel aditi's approach is okie dokie.......that must be it........

aditi_g

@netkid u didnt notice that the eqn on RHS is also multiplied by -ve sign apart frm 2

learner

Thanks a lot aditi !!!

Really neat !

learner

Hey but netkid, won't that give a complex answer?If you take 2 common,you'll get i*something..what is to be done after that?

netkid07

mmmm....did'nt notice that actually.....soo...go right after aditi's approach :)

learner

Ayt !!

Thanks all !!

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