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| physics chemistry maths science forums |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Sep 2007 18:59:40 IST
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Sep 2007 19:24:07 IST
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x= (ey - e-y)/( ey+ e-y)
=> 1/x = ( ey+ e-y)/(ey - e-y)
=> (1+x) / (1-x) = (ey)/( e-y ) = e2y
=> log(1+x) / (1-x) = 2y
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