(x-2)^(x-2)(x-4)>1 since (x-2) has to b >0 so we can take llog on both sides ..
taking log we get:
(x-2)(x-4)* log(x-2)>0... now consider several cases: i)2the abv lhs >0...so satisfies ii) x=3 LHS=0 so does not satisfy.. iii)x>3 LHS<0 .. so doesnt satisfy. iv) x=4 0.. so doesnt satisfy. v) x>4 LHS>0 so satisfies... so the solution is x =(2,3) U(4,infinity).....
Moderation Team
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