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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jun 2008 14:22:28 IST
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If matrix  raised to power k  , then what is the least positive integral value of k???
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Know thyself
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16 Jun 2008 14:27:25 IST
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plzz ny1 reply...
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16 Jun 2008 14:33:37 IST
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just keep on multiplying till u get any...is it 5?
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16 Jun 2008 14:34:48 IST
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Nopes da answer is 7
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16 Jun 2008 14:37:34 IST
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yea u keep on multiplying till u get cos2pi sin2pi
sin2pi cos2pi
please rate if correct
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16 Jun 2008 14:44:16 IST
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I am not getting it...plzzz explain in detail
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16 Jun 2008 14:50:33 IST
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see when u multply it with itself...
u get cos^2(2pi/7)-sin^2(2pi/7) cos2pi/7sin2pi/7-sin2pi/7cos2pi/7
sin2pi/7cos2pi/7+cos2pi/7sin2pi/7 cos^2(2pi/7P+sin^2(2pi/7)
then use cos^2theta-sin^theta to get cos2theta and use sin(a+b) formula
then keep multiplying it till u get the answer...that is multiply 7 times..i mean the matrix^7
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16 Jun 2008 14:51:34 IST
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But multipying 7 times will be a long process...
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16 Jun 2008 15:06:40 IST
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plzz tell wudnt it be too long..and what if we dunno da answer....how long shud we keep on multiplying???
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17 Jun 2008 20:00:44 IST
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The best method to do is not this as mentioned by above people.Previously,Man111 asked this question and I answered it there.Plz see this,
http://www.goiit.com/posts/list/algebra-question-61994.htm
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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