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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: matrix inverse doubt..
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sagar90 (204)

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if  A2+ I =0   I= identity matrix thn A-1?


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dheer_07 (241)

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A INVERSE = - A
plz  rate if im right
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hash_include (381)

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answer:

-i    0
0    -i

where i = root(-1)

JEE and OLYMPIA INFINATUM
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sagar90 (204)

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i also knw the answer but how it came?


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dheer_07 (241)

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WATS THE ANS???
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jeesucks (12)

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-A
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sagar90 (204)

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yaar give explanation .........


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sagar90 (204)

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common give the soln
otherwise how ur answer came thn??


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varshavallig (798)

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its simple
multiply A# in the front i.e pre multiplication.,then it will bcom
(A'A)A+A'I=0
IA+A'=0
A'=-A
hope this helps
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premsharma (19)

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yeah thats right
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fwks_phoenix (240)

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A2+ I =0   I= identity matrix thn A-1? '
 
AA-1=I
 
so
A2+I=A2+AA-1 = 0
       A(A+A-1)=0
A cannot b equal to zero since Inverse exists
        A+A-1 =0
so A-1 = -A


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sagar90 (204)

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http://www.goiit.com/posts/list/differenciation-limit-doubt-47692.htm
guys try this one (give full soln)
 
If A =  2  3  and A-1 = kA  thn k equals ?
          5  -2


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fwks_phoenix (240)

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in this case also inverse exists as det A is not equal to zero
 
so multiply on both sides by A
AA-1=kAA
AA-1=I
so kA2=I
now find A2, mltiply each element by k and equate the elements to that of I..u'll get k..
 
19  0  
 0  19  this is A2
 
and now kA
 
K19 O
0     K19
 
K19=1
K=1/19
 


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