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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:31:51 IST
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Bag I contains 3 red and 4 black balls and bag II has 4 red and 5 black balls. one ball is transferred frm bag I to II and then a ball is drawn frm bag II. the ball so drawn is red in clour. find the probablity dat transferred ball is black. Now suppose E1=event of ball transferred frm bag I is red E2= event of ball transferred frm bag I is black A- event of drawing red ball then wat is P(A/E1).....is it 1/2?? plz explain!!
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Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:36:28 IST
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2 cases: case 1: red ball is transfered from bag I to II this happens with prob of 3/7 now bag II has 5 red and 5 black balls probablity of picking red=5/10=1/2 so total probability for this to occur=3/7*5/10=15/70
Case 2: black ball is transfered this happens with chance of 4/7 now bag 2 has 4 red, 6 black so prob to pick red= 4/10 total probablity= 4/7*4/10=16/70
by bayes rule, P=probalbility that black was transfered/total probability =16/70/(16/70+15/70) =16/31
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:39:57 IST
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Re:ncert qn
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all the best ... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:40:04 IST
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P(A/E1) implies the probablity of E1 occuring given event A has already occured
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:40:55 IST
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its 16/31
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Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:41:29 IST
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thanx ...i wasnt sure abt P(A/E1)
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Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:41:52 IST
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the question asks prob that black was transfered....that is P(A/E2)
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:48:54 IST
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AKHIL U R WRONG
p(A/E1) implies probability of A given that E1 has already occured
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all the best ... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 22:00:28 IST
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E1 = red ball transffered frm bag1 to bag 2 E2 = black ball transffered frm bag1 to bag2
E1 n E2 r mutually exhaustive n exclusive
P (E1) = 3/(3+4)
P(E2) = 4/(3+4)
E = red ball is drawn frm bag2
P(E/E1) = 4+1/(4+1)+5 = 5/10
P(E/E2) = 4/4+(5+1) = 4/10
required propability = (usin bayers theorem) = 16/31
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 22:02:20 IST
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thanx all!!
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Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
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