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Hari Shankar's Avatar
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17 Jan 2008 19:50:19 IST
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If  = (n + (n2 - 4))/2 where n is an integer
 then prove that m = (k+(k2-4))/2 where k,m are natural numbers.


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Sairam's Avatar

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17 Jan 2008 21:47:29 IST
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hs bhatt,
the gvn eqn implies
 is aroot of x^2-nx+1
now to get da eqn whose roots are mth powers of orign eqn, raise x to xpower 1/m
so x^2/m - nx^1/m+1=0 has alpha power m as the roots
and the roots of dis eqn are also of d form k+sqrt(k^2-4)/2
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18 Jan 2008 09:31:55 IST
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You are only proving that (m)1/m= (n+ (n2-4))/2 = . We are back to square one.

We should be looking at x2m- nxm+1 = 0.

Abhijith's Avatar

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18 Jan 2008 16:14:56 IST
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Nice one indeed hsbhatt,
 
Ok first things first. The condition  should be true.
 
Let be defined as above. Then,
Fact: for any positive integer , the number is a positive integer.

Proof by induction on :
 
we have
 
 Thus
 
Now on, binomial expansion of the LHS and induction completes the proof.

Let by above Fact is a positive integer.
Since , we get:

Hari Shankar's Avatar

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18 Jan 2008 18:23:14 IST
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The working's fine.
 
Except that n>=2 need not hold.
 
You could use induction as follows
 
Assume m + 1/m = p (an integer)
 
Then (m+1) + 1/(m+1) = (m + 1/m) (+1/) - (((m-1) + 1/(m-1))
= an integer.
 
Its a little easier to understand.
 
By the way, if you are an IIT aspirant, your chances of getting in are pretty good.
Abhijith's Avatar

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18 Jan 2008 18:59:27 IST
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why do u say  need to be true? Wont  become complex otherwise?
 
yes i am an iit aspirant..12th std student..thanks a lot! i do hope i make it...
Hari Shankar's Avatar

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18 Jan 2008 21:40:49 IST
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can be complex no harm. Just go through each step of the soln and see if being complex is any hindrance.

U r sure to get IIT man. If you were stock, I would buy you for sure! Just make sure you pay this much attention to Phy and Chem too. They r just as imp.

Abhijith's Avatar

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19 Jan 2008 13:55:30 IST
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oh ok... and thanks for saying that!!!  i'll hav to work on chem...

New kid on the Block

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19 Jan 2008 18:32:03 IST
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Abhijith's Avatar

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20 Jan 2008 19:17:01 IST
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thanks sizzle!
abhishek gupta's Avatar

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15 Mar 2008 23:29:54 IST
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konichiwa2x (1302)
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16 Mar 2008 01:01:44 IST
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well, why did u bring up this old post now?



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