Home » Ask & Discuss » Mathematics. » Algebra « Back to Discussion

Algebra

Blazing goIITian

Joined:	25 Jul 2011
Post:	322

27 Dec 2011 11:40:40 IST

0 People liked this

204

Nice sum

Mathematics

the radius of a circle is 11m.......A,B and C start moving from a point at same time in a circle....A and B clocwise....C anticlocwise.....if A meets C in 88secs.....B meets C in 110 secs.....in what time will A meet B??????

Share this article on:

Comments (3)

hemang

Blazing goIITian

Joined: 27 Dec 2010

Posts: 1474

27 Dec 2011 12:06:34 IST

Like 0 people liked this

just take the values of their velocities as variables.

the sum of the distances travelled by them when they meet = the circumference.

this is not so with the case when A and B meet.

cause they are both walking clockwise.

i haven't solved it.

but maybe it will help...

sathyaram

Blazing goIITian

Joined: 25 Jul 2011

Posts: 322

27 Dec 2011 19:45:11 IST

Like 0 people liked this

i got it as 440 sec,right?

Manasi

Forum Expert

Joined: 1 Dec 2006

Posts: 2108

11 Feb 2012 19:15:57 IST

Like 0 people liked this

Let the respective speeds be a, b and c.

then when a, nd c meets, 88 (a+c) = 2X11Xpi => a+c = pi/4 .................(1)

when b and c meets, 110(b+c)= 2X11Xpi => b+c=pi/5 .................(2)

now, since a and b are moving in same direction, when they meet after time 't'

t (a-c) = 2X11Xpi .................subtracting (2) from (1)

=> t [(pi/4) - (pi/4) ] = 2X11Xpi

=> t = 440 sec

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team