IIT JEE , AIEEE Forum - Mathematics , Algebra

ssbrightstar1

A substance decomposes according to second order

rate law.If the rate constant is

6.8 x 10^-4 /mole/s,Calculate half - life of the

substance if the initial concentration is 0.05 mole/L.

risin

Second order=>

$-\frac{d[A]}{dt}=k{A}^{2}\;On \;integrating\;and\;applying\;limits:\frac{2}{[{A}_{0}]}-\frac{1}{[A{}_{0}]}=k{T}_{1/2}\\{T}_{\frac{1}{2}}=\frac{1}{{A}_{0}k}$

=>around 3*10^5

riku

no doubts..
its perfect..

arpan1

how many times do u ask the same ques man , huh !!!

risin

@riku:Thanks.

@ssbrightstar:Hope you understood

@arpan1:Might be he needs it fast.

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