Home » Ask & Discuss » Mathematics. » Algebra « Back to Discussion

Algebra

Hot goIITian

Joined:	24 Nov 2006
Post:	133

24 Feb 2007 06:46:38 IST

0 People liked this

527

on max and min

None

If an= (1000^n)/n! for n=1,2,3,..............then the sequence [ax]

a)does not have a maximum

b)attains maximum at exactly

one value of n

c)attains maximum at exactly 2 values of n

d)attains maximum at n=100

please nswer with explanation

Share this article on:

Comments (3)

Bipin Dubey

Forum Expert

Joined: 23 Jan 2007

Posts: 7942

27 Feb 2007 04:51:42 IST

Like 1 people liked this

1000ⁿ/n! = (1000/1).(1000/2).(1000/3)...................(1000/n)

For n = 1,2,3...........1000 this value is increasing since every term uptil here is greater than 1.

But for n>1000, 1000/n < 1 and the series would start decreasing since the series is multiplied by numbers less than 1.

Hence it attains a maximum value at n = 1000.

Best Wishes

tejasvi2389

Hot goIITian

Joined: 24 Nov 2006

Posts: 133

27 Feb 2007 13:15:54 IST

Like 0 people liked this

yes I too think the option should be 1000 but CD are given as answers please help

Bipin Dubey

Forum Expert

Joined: 23 Jan 2007

Posts: 7942

27 Feb 2007 17:58:07 IST

Like 0 people liked this

At n=999 and n=1000 the values are same hence they attain maximum for two values of n.

Option d has some misprinting it should be n = 1000 instead of n = 100.

Best Wishes

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team