I think the question is wrong. I can prove that 72C36 is not divisble by 73.

The factors of 72C36 are all less than 73. Also 73 is a prime number. Therefore it must be present in 72C36 so that it divides 72C36, but from the first statement it is not true.

I am not able to solve it (I'll keep on trying). Pls can anybody solve it.

I think its based on Wilson's theorem or can be done using it.I am trying..I am a beginner in number theory.

⁷²C₃₆ has factors less than 73.

Moreover, 73 is a prime number.

Hence ⁷²C₃₆ is not divisible by 73.

in the expansion of (1+1/73)⁷² the term (⁷²C₃₆)/73 -1/73 both r available with integral values hence we can say that ⁷²C₃₆ -1 is divisible by 73.

hope u got it......

Where did you even get a term called -1/73!  Thats complete rubbish!

in (1-1/73)⁷² will u not get 72.(1/73) as 2nd  term in the expansion taking 72 common from 72C36 and this we get the desired result.

at least put a liitle stress on ur brain man.

sorry to interrupt, but can you have a look at the sequence you provided in your previous post!?

And sorry, i dont have any brains at all, can you post a full proof, i dont seem to get your vague statements!

hey sandeepramesh I m very sorry for my misbehavior.No matter if our thoughts r not matching in this question but v r good friends.

Plz try man111 and my question.

ok animal, but i still dont get your method, mind explaining it?

Why should that part be divisible by 73 necessarily! This is clearly a number theory question and as Conjurer said, i too suspect, it shd involve Wilson's theorem!