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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Nov 2007 20:15:59 IST
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THE NUMBER OF ALL POSSIBLE SELECTIONS OF ONE OR MORE QUESTIONS FROM 10 GIVEN QUESTIONS,EACH QUESTION HAVING ONE ALTERNATIVE IS a) 3^10 b) 2^10 -1 c) 3^10 -1 d)2^10 THE ANSWER GIVEN IS (c) BUT I WOULD PREFER A DETAILED SOLUTION.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Nov 2007 22:13:23 IST
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i think the answer should be (b)..
coz total selections=
(selecting 1 ques)+ (selecting 2 ques )+ - - - - - - - - +(selecting 10 ques)
= 10C1 +10C2 +10C3 + - - - - - - - - - - + 10C 10 = 2^10 -1.............(B)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Nov 2007 23:03:47 IST
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BUT RINI IT ISIN'T THAT SIMPLE EACH QUESTION HAS ONE ALTERNATIVE WHICH HAS BEEN CLEARLY MENTIONED ABOVE.
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can you please clear what does one alternative mean because as far as i guess it with each question you have three options :
a) you select it b) you don't select it c) well, the alternative which is present
if this is what alternative means here then the answer can be expained as below: with each question you have 3 options so total ways you can select question is 3^10 here now we subtract 1 case where we don't select any question so the answer is 3^10 -1
rate me if correct
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Nov 2007 23:23:52 IST
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if "one alternative" means 2 choices, then here's the answer.
for each question u have 3 choices : option 1 , option 2, or to not select that question.
so for 10 questions u have 3^10 choices.
but u have to select one or more choices . so exclude the case where u do not choose any question. so answer is 3^10 -1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Nov 2007 23:46:46 IST
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each question can be handled in 3 ways either do the main question , or alternative , or leave it so total selections possible are 3 * 3* 3......10times = 3^10 but question says one or more selections so we remove the case in which the person leaves all the questions (i.e gives a blank paper) hence no. of cases = 3^10 -1
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"Imagination is more important than knowledge."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Nov 2007 09:44:58 IST
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ALL OF YOU HAVE DONE THE SAME THING AND I THINK THIS IS THE CORRECT SOLUTION BUT THE DOUBT I HAVE IS EVERY QUESTION HAS ONE ALTERNATIVE SO YOU CAN EITHER SELECT THE MAIN QUESTION OR THE ALTERNATIVE OR BOTH OR NONE OF THEM, SO EACH QUESTION CAN BE SELECTED IN 4 WAYS???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Nov 2007 19:04:29 IST
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no mudit how cannot select both the main & the alternative question because you have to do any one of them that's why the name is ALTERNATIVE question
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Nov 2007 22:59:34 IST
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THANKS A LOT PRIYESH.
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