| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Mar 2008 22:54:11 IST
|
|
|
find the +ve integral soln for x1x2x3x4x5=840 see my method... 840=23.3.5.7 now 3 can be placed in five spaces in 5 ways.. now 5 can be placed in five spaces in 5 ways.. now 7 can be placed in five spaces in 5 ways.. now 23 ..............plz explain this part....all three 2's i.e 23 can be placed in five spaces in 5 ways....also 22X2 this can be done also it can be divided into 2X2X2...so plz explain how to do....rate for coreect answer///
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
|
|
|
24 Mar 2008 22:54:58 IST
|
|
|
what do u want to ask man
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:00:59 IST
|
|
|
sorry edited...
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:01:46 IST
|
|
|
wow now that u have posted the ques i cant answer it.........
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:08:35 IST
|
|
|
wat do u mean by it...plz clear my doubt anyone.....
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:13:14 IST
|
|
|
anyone going to help me???/or not???somebody plz reply....
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:14:49 IST
|
|
|
edited
its equivalent to filling
5 boxes with 10 items
where 3 items of 1 kind are alike (2's)
and 4 items of oder kind r alike (1's)
see y so.
x1,x2,x3,x4 all can be 1, x5 can be 840...--thats d reason y i say 4 1's
and remaining (3,5,7) are distinct
|
this reply: 4 points
(with 0
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:25:37 IST
|
|
|
ya...so..pzl tell the no. of ways of puttin (2)powr 3 in 5 boxes.....
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:30:32 IST
|
|
|
plz solve and post the answer....
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:41:20 IST
|
|
|
where have all the people gone???none to solve a small ques?????
|
The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:43:22 IST
|
|
|
k fine
ill do it.wats d ans?
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
24 Mar 2008 23:54:46 IST
|
|
|
edited
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
25 Mar 2008 00:03:00 IST
|
|
|
K fine'
Im not verry sure..neways,
the approach i had given u earlier was my own, bt its quite long,
heres anoder method
2^3*3*5*7
=x1x2x3x4x5
now3,5,7 can be assigned 2 any of d 5 variables, 5^3
as for 2^3
it can b assigned to 1 variable in 5 ways, 2 variables in 10*2 ways (5c2) *2 for
(1,2) and (2,1) they r diffn here
3 variables in 10 ways (5c3) thus total=35 ways,
now total no of ways=
35*5*5*5=4375
edited:
gokuls rt
i hadnt taken care of (2,1) and (1,2) permutation wen i distr. 2^3 to 2 variables
now its corrected
|
this reply: 15 points
(with 3
in 3 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
25 Mar 2008 00:12:54 IST
|
|
|
5*5*5 thts ob
the other val will be a) no 2s r together: 5C3=10
b) one gets two 2s n other one 2=20
this can be said from: select one box n put two 2s..5ways
from remaining 4 boxs select 1 for other 2..so 5*4=20
c)one gets all 3 2s=5
so v get 5*5*5*35=4375
|
Nitwit Blubber Odment Tweak
|
this reply: 25 points
(with 5
in 5 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
25 Mar 2008 00:24:53 IST
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
