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25 Oct 2007 11:53:46 IST
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pal_sodhi91
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Q. Find the number of positive integral solutions for :
3x+y+z<=30
25 Oct 2007 12:12:37 IST
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raja987654321
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For 3x+y+z<=30
y+z<=30-3x
Now no of positive inteagral solution for this is
C(29-3x,1)=29-3x (for all x>0 & x
I)
Hence x=1,.....,9
Thus 9 possible inteagral solutions
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25 Oct 2007 12:24:01 IST
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given condition :: x,y,z>0 & 3x + y + z <=30
=> y+z <= 30-3x
=>ordered pairs of form ( y,z ) which satisfies this is
30 - 3x -1= 29 - 3x
x can vary from 0 t0 9
total solutions = Summation [ 29 - 3x ] ( from x=1 to x=9)
= ( 29x9) - 3x45
=126
............tseb eht ma i
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25 Oct 2007 12:24:27 IST
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and yeah....do giv me rates... :D
............tseb eht ma i
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25 Oct 2007 15:19:47 IST
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raja987654321
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sry my soln incomplete u need add up the combination results for for the values of x=1,.....,9
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