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Ask iit jee aieee pet cbse icse state board experts Expert Question: permutation and combination
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ayush_2711 (7)

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find the no. of ways of arranging the letters of the word GARDEN so that the vowels are arranged in alphabetical order.
 
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Anvesh (0)

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2!*4!=48
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rahul_c (188)

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             G  A  R  D  E  N          
 
since the vowels are in alphabetical order E should always follow A
 STARTING FROM LEFT
 
 A AT 1ST POSITION E CAN BE PLACED AT REMAINING 5 PLACES =5C1*4!
 
 A AT 2ND POSITION E CAN BE PLACED AT REMAINING 4 PLACES =4C1*4!
 
 A AT 3RD POSITION E CAN BE PLACED AT REMAINING 3 PLACES =3C1*4!
 
 A AT 4TH POSITION E CAN BE PLACED AT REMAINING 2 PLACES =2C1*4!
 
 A AT 5TH POSITION E CAN BE PLACED AT REMAINING 1 PLACES =1C1*4!
 
 A  AT 6TH POSITION E CANNOT BE PLACED AT REMAINING PLACES OTHERWISE E WOULD COME BEFORE A
 
THEREFORE TOTAL NUMBER OF WAYS= 4!*(5C1+4C1+3C1+2C1+1C1)=360 WAYS

The yardstick of human intelligence is the ability to overcome the last fallacy
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uday_sravan (5)

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Total number of ways in which letters of word GARDEN can be arranged in 6! ways. In these half will have letter A before letter E. Therefore required answer is 6!/2=360
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vaibhavbright (160)

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see   just refer to dis solution
 
The Ans    is                     360  
 
 
wat u have to do in such kind of ques  --------    take d vowels ( in this case  A  &  E ) as alike
n then use d formula 
 
alike  bcoz    d vowels can be arranged but not bw themselves
 
so d ans comes    6! / 2!   =   720 / 2  =  360

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vaibhavbright (160)

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see   just refer to dis solution
 
The Ans    is                     360  
 
 
wat u have to do in such kind of ques  --------    take d vowels ( in this case  A  &  E ) as alike
n then use d formula 
 
alike  bcoz    d vowels can be arranged but not bw themselves
 
so d ans comes    6! / 2!   =   720 / 2  =  360

VAIBHAV BEST
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ayush_2711 (7)

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VAIBHAV, CAN YOU PLZ..EXPLAIN WHY THAT 2! COMES IN THE DENOMINATOR AND ALSO WHICH FORMULA YOU ARE USING?
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krishna.gopal (2149)

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The answer is 360 as rightly pointed by uday and Vaibhav. Rahul here you should appriciate the way uday solved the problem. A bit of applications at times can save you hell lot of time.
      And what Vaibhav is saying is a general case solution for this problem. The 2! comes because you are taking A and E as identical.
Remember number of ways to arrange n things out of which r are identical is n!/r!  

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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ayush_2711 (7)

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Thankyou
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