The total no. of combinations of 2n different things taken any one or more at a time is given by
2nC1+ 2nC2 + 2nC3+ 2nC4 +... + 2nC2n = 22n - 1 .......(1)
Similarly, the total no. of combinations of n different things taken any one or more at a time is given by
nC1+ nC2 + nC3+ nC4 +... + nCn = 2n - 1 .......(1)
Further it is Given that
(22n - 1)/(2n - 1) = 65/1
let x = 2n
therefore, (x2 - 1)/(x - 1) = 65/1
or x + 1 = 65
or x = 64
or 2n = 64
or n = 6
I guess the problem is clear and understandable now