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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Apr 2007 20:56:06 IST
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Hi,
The least common multiple of three integers x,y,z is  How many ordered triplets of the form (x,y,z) can be formed such that their LCM is ?
How do I do this problem? thanks.
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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25 Apr 2007 21:14:00 IST
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hi this is for cases of (x,y) ordered duplet extend by taking cases for three nos.
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25 Apr 2007 21:23:21 IST
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this is the way to do:
now as the thing r^5 is in the lcm thus at least one no.must have r^5 as its factor. thus let p has r^5 as one of its factors and q can have r^0 or r^1 or r^2 or r^3 or r^4 or r^5 as its factors. similarly q has one of its factors r^5 and p has r^0 or r^1 or r^2 or r^3 or r^4 or r^5 as factors. thus total 9 cases not ten as we wont count the case twice which is p = q = r^5.
similarly u can do with t .
final answer: this is for cases of (x,y) ordered duplet extend by taking cases for three nos.
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25 Apr 2007 21:28:26 IST
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plz rate if correct
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