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I made three groups of prizes,
grp 1 = (2,1,1) = ^{3}C1^{4}C_{2}^{2}C_{1}
grp 2 = (3,1,0) = ^{3}C_{1}^{2}C_{1}^{4}C_{3}
grp 3 = (4,0,0) = ^{3}C_{1}
grp 4 = (2,2,0) = ^{3}C_{1}^{2}C_{1}^{4}C_{2}
adding = 36 + 24 + 3 + 36 = 99
typing each letter on keyboard really sucks............
yup,
I got it, it was easy,
place 4 prizes stationary on table,
now each prize can be own by single person,
so.
prize 1 can be taken by either of 3 students i.e ^{3}C_{1},
similarly,
for prize 2,3,4 i.e. ^{3}C_{1}
Total = ^{3}C_{1 }^{3}C_{1}^{3}C_{1}^{3}C_{1 = }81
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