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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Apr 2008 16:35:23 IST
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What is the maximum no. of points of intersection of 8 circles??
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7 Apr 2008 18:52:46 IST
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7 Apr 2008 18:54:36 IST
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another simple way is 2*(8C2) as two circles gives 2 pts and 2 can be chosen in 8C2 ways...
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8 Apr 2008 16:27:55 IST
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edited.. sorry sboosy. i made a terrible mistake..
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8 Apr 2008 18:35:12 IST
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Hash , i think my answer is correct , infact there is a sur mistake in ur general form
u have said it is of the form n^2+n , where n according to u is the number of intersecting circles.
Now lets come back to the basic case (n=2) that is 2 circles intersecting
according to ur formula we'll get
2^2+2 = 6
we know that the answer is not 6 and it is 2 rather
And i also think i understand what u meant to do ..
only thing in ur formula that n should stand for the number of circles - 1
that way 2 circles means 1^2+1 = 2(which is right)
3 circles means 2^2+2 = 6(which is right)
and likewise
8 circles means 7^2+7 = 56
which is exactly what ive got
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9 Apr 2008 02:00:12 IST
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well according to me the MAAAAXIMUM no of points is INFINITE draw all the 8 in the same place  |
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