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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2007 21:59:04 IST
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c02+c12+c22+...............................+cn= (2n!) / (n!)2
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enjoy life every moment..............................
sneha kulkarni................
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21 Mar 2007 22:06:04 IST
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hey, first write down the binomial expansion of
(1+x)^n two times.
now, multiply, both the series and find the coefficient of the series u want.
little difficult to explain. hope u understod !
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21 Mar 2007 22:07:49 IST
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no.........pls tell me more..in detail..pleaseeee
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enjoy life every moment..............................
sneha kulkarni................
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21 Mar 2007 22:09:00 IST
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ok, one minute please!
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Z = Co2 + C12 + C22 + C32 + .........................+Cn2 (1+ X)n = Co + C1 X + C2 X2 + ...................+ Cn Xn ----------------------(1) (X+ 1)n = CoXn + C1 X n-1 +.......................+ Cn -----------------------(2) MUTLIPYLING (1) AND (2) :: (1+ X)2n = ................. + (Co2 + C12 + C22 + C32 .........................+Cn2)Xn +........................................... NOW, U WANT THE VALUE OF Z WHICH IS THE COEFFIECIENT OF XN IN THIS SERIES WHICH IS EQUAL TO THE VALUE ON RHS. DO ASK IN CASE OF DOUBT ~
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21 Mar 2007 22:21:08 IST
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u got it ??????
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21 Mar 2007 22:23:29 IST
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yeah i got it..........thanks a lot
i'll ask if i m in doubt......k
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enjoy life every moment..............................
sneha kulkarni................
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21 Mar 2007 22:45:27 IST
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hey i got it!!!!!!!!!!! now..........
thanks a lot.........
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enjoy life every moment..............................
sneha kulkarni................
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21 Mar 2007 23:02:49 IST
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u r welcome ~
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21 Mar 2007 23:07:34 IST
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meanwhile check ur nudge book !
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