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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jan 2008 10:11:31 IST
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SHOW THAT (1-  + 2) ( 1- 2 + 4) (1- 4 + 8 )..........TO 2N FACTORS = 2 N
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jan 2008 10:24:09 IST
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1+w+w^2=0 1+w^2=-w sub in eqn similarly w^4=w therefore 1+w=-w^2,w^8=w^2therfroe(1-w^4+w^8)=(-2w) (-2w)(-2w^2)(-2w)...........upto2n factors=2^n hence proved(becuase first two terms becomes 4 hence all terms will become four
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jan 2008 10:24:10 IST
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(1 - w + w^2)(1- w^2 + w^4)(1 - w^4 + w^8)............to 2n factors
= ( 1 - w + w^2)(1 - w^2 + w)(1 - w + w^2)..........upto 2n factors
( since, w^4 = w , w^8 = w^2 , w^16 = w.......)
=(-2w)(-2w^2)(-2w)(-2w^2)............to 2n factors
= (2^2w^3)(2^2w^3)(2^2w^3).........upto 2n factors
= 2 ^2n.......proved
Hope it helped.Nudge if not clear.Rate if satisfied.
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Not all who wander are lost
The old that is strong does not wither,
Deep roots are not reached by frost.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 08:54:31 IST
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yes the ans comes 22n
see the above method
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