then,solve the matrix.....

row 1: I pa qb rc I

row 2: I qc ra pb I

row 3: I rb pc qa I

GIVEN: p+q+r=a+b+c=0

PLS GIVE ME A SOLUTION

  Let D =

=Opening the D with Sarru's formula....

D = pa.ra.qa + qc.pc.rc + rb.pb.qb - [ ra.rb.rc + pa.pb.pc + qa.qb.qc]

D = pqra³ + pqrc³ + pqrb³  -  [ r³abc + p³abc + q³abc]

so... D = pqr [ a³ +  b³ + c³ ]  - abc [  p³ + q³ + r³ ]

but as we know.....if a + b + c =0 then.......a³ +  b³ + c³ = 3abc

so...D = pqr [3abc]  -  abc[3pqr]

so...D = 0....

hope its clear.....