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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 May 2007 18:49:13 IST
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how to find a largest term in a expansion when the value of x is specified?
anybody plz answer this
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 May 2007 20:59:22 IST
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well i dont know soo well nut here is my try at this
If (x+a)n is the expression we can expand it thru binomial theorem there are three possibilities:
if x>a: then nC0 xn will be the highest
if x=a: nCn/2xn/2an/2 will be the highest
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In the process of learnin..............blunders do happen !!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 May 2007 21:30:18 IST
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i think ur approach is wrong consider this (1+2)^20 according to u it is 20c20 2^20 but consider the term before it i.e 20c19 2^19 which is greater than the above i dont know the process actually but urs is wrong
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GBXDHNXDFNHBHRSDRGWEASGSEDH |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 May 2007 23:51:18 IST
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ya the above one works only if n<x>a
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In the process of learnin..............blunders do happen !!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2007 00:12:27 IST
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u r correct
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now got it .... and when n>x>a
the general term is nCrxn-rar the coefficient of all the terms after n=x will be more than xn Here we are concerned with the coefficient only: nCr = n!/[(n-r)!r!]
therefore the largest term will be that term where r satisfies or nearly satisfies the following condition: (n-r)!r!=x!
do rate me if i am correct
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In the process of learnin..............blunders do happen !!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2007 06:14:15 IST
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thank u
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