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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: plz. help me
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rich_1986 (0)

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-1--1--1-..............
    
infinitestrength (0)

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if infinity is even then soln is 0
if  infinity is odd then soln is "i"
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spideyunlimited (3912)

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infinty is neither even nor odd...
rich_1986 i think ur question is wrong...
the one we CAN solve is where there are all + signs not - sign

and the under root sign is over all of them naa?

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spideyunlimited (3912)

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anyway i think the answer is i/2 (iota / 2)

let .. root -1 - root -1 - root -1... upto infinity = y

then y = root -1 - y
2y = root - 1
y = i /2


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rajatsen91 (817)

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let x= root -1 - root -1 - root -1...
x^2=-1-x
therefore x^2+x+1=0
so
(x+w)(x+w^2)=0
therefore x= w or w^2 ( where w and w^2 are the complex cube roots of unity)

I like to be myself.
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rajatsen91 (817)

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The question is right and infinite strength you have the word infinite in your profile name and you do not even know that infinity is not a real number.

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b_srikalyan009 (350)

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the question is not what u think.only rajetsen is right
it goes in this way
 
hence if y is the ans
y=[2 ](-1-y)
squaring on both the sides
 
y^2= -1-y
 
y^2+y+1=0
 
hence ans is w & w^2
 




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mikans (36)

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the ans is 1/2 i suppose




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metal (341)

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We know that -1 = i
so, the question can be written as i-i-i-i.........till infinity, [if I have understood the question properly.]
The first two i cancel out. So the expression becomes -i-i-i-....till infinity.
Take the negative sign common.
you get -{i+i+i........till infinity}
the thing within the bracket is an infinite A.P. with common difference > 0 and the sum of such a series is always = infinity.
So the final answer is  {-infinity}, if my interpretetion of your question is correct.
      
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b_srikalyan009 (350)

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@metal i dont think the is in that way.
in that case u cannot solve the question.
what i and rajetsen did is absolutely right.
otherwise the question makes no sense.
what i have done is i assumed the summation to be y.
if u ignore one term in is the same as the sum is to infinity.



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metal (341)

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Yes, I get it. I was wrong. Thank you.
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spideyunlimited (3912)

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read my method above n temme whts wrong with it then

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mk_suhas (196)

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hey spideyunlimited,   this is where u have gone wrong

when        -1--1--1-..............

u took y =
  -1--1--1-..............       ok i agree
later,  y =
-1-y

now the mistake is, u have taken 2y = i
actually, the y is within brackets, so it can't be taken as 2y

So here's the solution..
y2 = + or - (-1-y)


now go on n get 2 solutions!
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