| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 13:05:40 IST
|
|
|
-1- -1- -1-..............
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 13:31:27 IST
|
|
|
if infinity is even then soln is 0 if infinity is odd then soln is "i"
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 13:37:19 IST
|
|
|
infinty is neither even nor odd... rich_1986 i think ur question is wrong... the one we CAN solve is where there are all + signs not - sign
and the under root sign is over all of them naa?
|
---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 13:39:28 IST
|
|
|
anyway i think the answer is i/2 (iota / 2)
let .. root -1 - root -1 - root -1... upto infinity = y
then y = root -1 - y 2y = root - 1 y = i /2
*PLZ RATE*
|
---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 17:40:18 IST
|
|
|
let x= root -1 - root -1 - root -1... x^2=-1-x therefore x^2+x+1=0 so (x+w)(x+w^2)=0 therefore x= w or w^2 ( where w and w^2 are the complex cube roots of unity)
|
I like to be myself. |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 17:52:16 IST
|
|
|
The question is right and infinite strength you have the word infinite in your profile name and you do not even know that infinity is not a real number.
|
I like to be myself. |
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 18:10:44 IST
|
|
|
the question is not what u think.only rajetsen is right it goes in this way hence if y is the ans y= [2 ] (-1-y) squaring on both the sides y^2= -1-y y^2+y+1=0 hence ans is w & w^2
|
    
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 18:11:48 IST
|
|
|
the ans is 1/2 i suppose
|
    
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 20:04:16 IST
|
|
|
We know that  -1 = i so, the question can be written as i-i-i-i.........till infinity, [if I have understood the question properly.] The first two i cancel out. So the expression becomes -i-i-i-....till infinity. Take the negative sign common. you get -{i+i+i........till infinity} the thing within the bracket is an infinite A.P. with common difference > 0 and the sum of such a series is always = infinity. So the final answer is {-infinity}, if my interpretetion of your question is correct. please rate me
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 20:56:41 IST
|
|
|
@metal i dont think the is in that way. in that case u cannot solve the question. what i and rajetsen did is absolutely right. otherwise the question makes no sense. what i have done is i assumed the summation to be y. if u ignore one term in is the same as the sum is to infinity.
|
    
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 21:04:03 IST
|
|
|
Yes, I get it. I was wrong. Thank you.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Aug 2007 17:23:12 IST
|
|
|
read my method above n temme whts wrong with it then
|
---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Aug 2007 17:32:47 IST
|
|
|
hey spideyunlimited, this is where u have gone wrong
when -1- -1- -1-..............
u took y = -1- -1- -1-.............. ok i agree later, y = -1-y
now the mistake is, u have taken 2y = i actually, the y is within brackets, so it can't be taken as 2y
So here's the solution.. y2 = + or - (-1-y)
now go on n get 2 solutions!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|