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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Mar 2007 21:04:46 IST
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hey ! can ne one tell me that if it is given that a cubic equation has 1 real and 2 imaginary roots, what information can we get about the graph of the function . (bascially not only a cubic equn. but any equation of degree n ) also in case of a cubic equation ,how many points will there be where f'(x) = 0 (where f(x) is the cubic equation )
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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14 Mar 2007 08:59:30 IST
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c mon ppl.what happened to all the maths experts.this is a good doubt ,can help u in objective problems !!!
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14 Mar 2007 18:55:50 IST
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reply ppl.wats wrong wid u ??
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15 Mar 2007 09:34:08 IST
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WTH,are u ppl sleeping ??
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15 Mar 2007 09:34:35 IST
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WTH,are u ppl sleeping ?? 43 views and 0 reps !!!
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19 Mar 2007 12:21:01 IST
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ohhh now cmon ..................... lithargic mammals !!!
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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19 Mar 2007 12:30:40 IST
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If a cubic equation has 1 real and 2 imaginary roots then its graph cuts X-axis at only one point.
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ADARSH
NITK Surathkal
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19 Mar 2007 12:45:51 IST
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ok thanx , for ur response but of course i know that it will cut the axis at 1 point.but can we say that there exists at least 2 points where f ' (x) = 0(just like in the case of 3 real roots ) or is it that we cant comment about the derivative being zero anywhere
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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19 Mar 2007 17:43:24 IST
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real roots says it intersect with x-axis
f(x)=ax3+bx2+cx+d
f ' (x)=3ax2+2bx+c
so for 2 real roots b2 should be greter than 3ac.
take an example x3-x2+x-1=0
have 1 real root but do not have 2 real point where f ' (x) = 0
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19 Mar 2007 18:19:05 IST
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~~~~~~~~~~~~~~~~HEY RAJAT ~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~ I DOUBT IF THIS ~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~ CAN BE SAID FOR IMAGINARY WORLD~~~~~~~
~~~~~~~~~~~~TELLS ONLY OF INTERSECTION~~~~~~~~~~~~~~
~~~~~~~~~~~ WITH x AXIS~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~`NOT SURE ~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~DON'T KILL THIS NOW~~~~~~~~~~~~~~
~~~~~~~~~~~~ASK TO EXPERTS~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~ GOOD CONFUSION~~~~~~~~~~~~~~~~~~~~~~~
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everything's fair in love , war and IIT JEE
   
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19 Mar 2007 18:34:16 IST
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ok f(x) cuts the x-axis only at one point but it is not necessary that there wont be any point where f'(x) = 0
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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19 Mar 2007 18:37:37 IST
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~~~~~~~~~~~gimme~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~ a quest.~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~shall try~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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everything's fair in love , war and IIT JEE
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19 Mar 2007 19:06:10 IST
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yes it is not neccesary that it wont have any point where f '(x)=0
but in general we cant say that it will have these point or not.
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