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Algebra
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Hari Shankar
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Joined: 28 Feb 2007
Posts: 2173
20 Jan 2008 07:29:25 IST
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Anybody have a look at this yet?
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23 Jan 2008 15:02:40 IST
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well, i think the condition should be given that a, b, and c are distinct. Otherwise a=b=c=0 (considering a polynomial with no constants) satisifes. So contradicts.
Let
be a polynomial with integer coefficients and
and
be two integers. Then
is divisible by
----(1)
be a polynomial with integer coefficients and
and
be two integers. Then
is divisible by
----(1)Proof:
now suppose we have
and
then by (1) we get,
and
so
and
, for some integers
and
and
then by (1) we get,
and
so
and
, for some integers
and
So
Hence
Thus
and
Hence
Thus
and
That gives us
now by (1),
but
Thus
, which is impossible....answer follows.
now by (1),
but
Thus
, which is impossible....answer follows.23 Jan 2008 18:54:58 IST
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Great stuff!
And the forum must thank you for introducing this concept that P(a) - P(b) is div by (a-b). It is very useful in many problems but I encountered this funda only recently.
Good going. And thanx again for pointing out my carelessness in conditions.
And the forum must thank you for introducing this concept that P(a) - P(b) is div by (a-b). It is very useful in many problems but I encountered this funda only recently.
Good going. And thanx again for pointing out my carelessness in conditions.











