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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: prob
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manjotpahwa (19)

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A doctor is to visit a patient. From the past experience, it is known that the
probabilities that he will come by train, bus, scooter or by any other means of
transport are respectively
3 ,1, 1 and2
10 5 10 5 . The probabilities that he will be late
are
1,1and 1
4 3 12 if he comes by train, bus and scooter respectively, but if he comes
by other means of transport, then he will not be late. When he arrives, he is late.
What is the probability that he comes by train.
 
ans is 5/7????

alphawoman1
    
avi_1214545 (974)

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i m getting 1/2
are these values correct??
if yes, plz give the values again..as they are not properly typed...

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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manjotpahwa (19)

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3/10, 1/5, 1/10, 2/5 resp fortrain bus scooetr and other
prob that hell be late is
1/4, 1/3, 1/12 and 0 resp

alphawoman1
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hash_include (381)

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answer is 1/2 only..
simple application of baye's theorem solves it..

JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php

join the revolution!!
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avi_1214545 (974)

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agree with @hash_include

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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srini (305)

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HEY,
IT IS 1/2... A READER SSUM...
P(T)=3/10,P(B)=1/5,P(S)=1/10 ANS P(OTH)=2/5
P(L/T)=1/4,P(L/B)=1/3,P(L/S)=1/12,P-(L/OTH)=0
 
P(T/L)=  P(T)P(L/T)/[P(B)P(L/B)+P(T)P(L/T)+P(S)P(L/S)+ P(OTH)P(L/OTH)]
=1/2.

GIVE LIFE THE BEST....srini...
DO OR DIE, OR BETTER NEVER TRY!!
I dont want to be the most intelligent among the ten.i pray the other nine RE fools!???!!!!!!
it doesn't matter if you win... whats important to me is i win!!!!!!!!
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