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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 23:52:40 IST
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A manufacturer of screws knows that 4% of his product is defective. If he sells the screws in boxes of 50 and guarantees that not more than 2 screws will be defective, what is the probability that a box will fail to meet the quality?
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alphawoman1 |
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19 Mar 2008 21:15:03 IST
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anyone who knws pls ans
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alphawoman1 |
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19 Mar 2008 21:23:16 IST
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probability that 0 are defective:
P1=(0.96)^50
probablity that 1 is defective
P2=(0.96)^49*(0.04)*50C1
probablity that 2 are defective
P3=50C2*(0.96)^48(0.04)^2
now required P= 1-(P1+P2+P3)
because none of the above cases shd hold true
P==1-0.9648(50C2(0.04)2+50(0.04)(0.96)+(0.96)2)
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19 Mar 2008 21:25:50 IST
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thnx but the p3 shud have 50c2 rite not 5c2
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alphawoman1 |
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