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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Nov 2007 09:20:43 IST
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If 2 cards are drawn from a pack of cards, then the probability of selecting both from the same suit or both kings is ----------------
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15 Nov 2007 09:54:21 IST
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no. of ways of selecting cards from same suit = 13C2
total ways of selecting 2 cards = 52C2
no. of ways of selecting 2 kings = 4C2
so probability of selecting 2 cards fro same suit or 2 kings = 13C2/52C2 + 4C2/52C2
= 78+6/26*51 = 84/26*51 = 14/13*17 = 14/221
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15 Nov 2007 18:42:23 IST
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Well...that is not the right answer..the answer is 53\221.
It comes under the addition theorem of probabilty....can som1 solve this plzzz
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Nishant,
13C2 will have to be considered 4 times as there are 4 suits.
(4x13C2 + 4C2)/52C2 gives the answer as 53/221
-Rohil
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