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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Dec 2007 17:44:01 IST
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Q.The odds in favour of A winning the game of chess against B is 5:2 .if 3 games are played then the odds in favour of A in winning at least one game is?
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16 Dec 2007 20:38:36 IST
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odds in favour of A winning the game of chess against B is 5:2
implies probab of winning for A = 5/2+5 = 5/7
now use binomial distribution.
P(a) A losses all = (2/7)^3
so probab A win atleast one game = 1 - (2/7)^3
plz rate if helpful
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16 Dec 2007 20:44:37 IST
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so odds in favour will be P(a):P'(a)
its 524.22:1 i think.
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16 Dec 2007 21:54:01 IST
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pannaguma is right............but pannaguma odds in favor must be 335/8 naa???? .....since P[A]=335/343 ,P[A^]=8/343
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"Nenenthedhavano naake teleedu"
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18 Dec 2007 21:58:16 IST
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yeah harsha ur right, i made a mistake.
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