IIT JEE , AIEEE Forum - Mathematics , Algebra

trisha

If a word is formed at random by using all the letters of the word 'ENGINEERING',then find the probability that the vowels are in alphabetical order.

KAB

There are 3E, 2I,3N and 2G.Total no of ways of arranging the letters of the word ENGINEERING is 11!/(3!*2!)²

Let EEEII be 1 unit.

The no. of ways in which vowels are in alphabetical order is =7!/(3!2!)

So required probability =[7!/3!2!]/(11!/(3!*2!)²)=3/1980

Plz experts tell me am I correct???

vish0001

adarsh, u have not calculated the probability of the number of ways in which words """ EEEII """"" can be permuted among themselves !

KAB

There is only one way EEEII thats all.

trisha

The answer given is 0.1

trisha

plzz tell me if u get 0.1

sudeep.kumar

Dear Trisha,

You have already asked and accepted the ans. of this question... do you have some doubt???

http://www.goiit.com/posts/list/4388.htm#22563

KAB

Sir plz tell me where I am wrong so that I can correct it.

sudeep.kumar

Look.... when you have counted the total no. of favourable cases in the second part.. you have neglected the relative arrangement of vowels and consonants, you have just rearranged the consonants among themselves...

so, EEEIINRNGNG

EEENRNGNGII

EENRENIGING etc all will be counted as just one case... as all have same relative arrangement of 3 N's, 2 G's and a R.

Got it???

KAB

Thank you Sir for correcting me.I forgot that vowels need not be together.

trisha

i have no doubt sir.sorry

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