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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:27:08 IST
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In a hurdle race, a player has to cross 10 hurdles. the probability that he will clear each hurdle is 5/6. what is the probability that he will knock down fewer than 2 hurdles. (NCERT TBQ Probability Misc. Q-6) plz reply soon
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:31:57 IST
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ans is (5/6)10 + 10C1(5/6)9 x (1/6)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:33:32 IST
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oh i know the answer plz give the solution
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:33:45 IST
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prob to knock down 1 hurdle: 1/6
so in 10 jumps, prob to knock down only one hurdle: 10*1/6*(5/6)^9 for no hurdle knocked down: (5/6)^10
so total P=10*1/6*(5/6)^9+(5/6)^10 =(5/6)^9(15/6) =(5/6)^9(5/2)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:39:08 IST
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is that a binomial trial
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:39:42 IST
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YES IT IS
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:42:32 IST
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sorry...what is 'binomial trial'? technical terms out of my reach!
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- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:48:01 IST
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plz solve this question for me too
a die is thrown again and again until three sixes are obtained. find the prob. of obtaining the third six in the sixth throw of the die.
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The deepest secret is that life is not a process of discovery, but a process of creation. You are not discovering yourself, but creating yourself anew. Seek therefore, not to find out who you are; seek to determine who you want to be."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:49:36 IST
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ok see fix the 3rd six in the sixth throw.. this means that 2 sixes have already appeared in past 5 throws so we have 5C2*(1/6)^3*(5/6)^3
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:51:34 IST
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ANS. IS 5C2 x (1/6)2.(5/6)3.(1/6)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 11:51:52 IST
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u need to think only abt 1st 5 throws so it'll be (1/6)^2*(5/6)^3*1/6 the last 1/6 accounts 4 the final throw but getting 2 6s from 1st 5 is 5C2 ways so v have 5C2(1/6)^2*(5/6)^3*1/6 EDITED: seeing tht as usual i posted solution just after akhil did pls dun rate :D
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