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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Mar 2008 14:47:03 IST
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A draw two cards at random from a pack of 52 cards.After returning them to the pack and shuffling it,B draws two cards at random.The probability that there is exactly one common card is.................. Ans is 50/663
Plzzz explain every step.Good explained ans will be given a minimum of 5 SALUTES.....for sure..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Mar 2008 15:03:02 IST
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let the cerds 'A' got be x and y; to find probability of getting atleast any one of x or y;
ie,Required probability= probability of getting x common OR y common OR both x & y;
P(getting x common)= P(getting x in 1st draw)+P(getting xin 2nd draw); =1/52+1/51 =103/2652; similarly getting y common=103/2652;
getting both common=2/C(52,2); =4/2652;
So, Probability=(103+103+4)/2652 =210/2652 =105/1326
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Mar 2008 15:04:05 IST
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Suppose A takes out cards named x and y Now its B's turn , he has to take out card x in his first draw and any other card in his next draw except card y . This has probability 1/52*50/51 and since he can take out other card first and card x in second draw so his probability is 1/52*50/51*2
Now also we can repeat the same solution for card y which again has probability 1/52*50/51*2
Adding the two probabilities we get 1/52*50/51*2 + 1/52*50/51*2 = 50/663
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"All of us are God's creatures... just some are more creature than others." |
this reply: 5 points
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Mar 2008 15:05:17 IST
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this reply: 17 points
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