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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Apr 2008 12:01:19 IST
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Q.Two persons A and B throw a dice each .If A throws a sum of 9 then the probability of B throwing a sum greater than that of is? 1.1/6 2.1/9 3.1/54 4.1/2
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if it is a pair of dice
for 10 - 5,5 or 6,4 so 3 ways
11 - 5,6 or 6,5 2 ways
12 6,6 1 way
so P=3+2+1=6/36=1/6
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19 Apr 2008 17:58:15 IST
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The possible outcomes are 10, 11 or 12.
ways of getting 10 - 4,6 ; 5,5 ; 6,4 3 ways
ways of getting 11 - 5,6 ; 6,5 2 ways
ways of getting 12 - 6,6 1 way
Total = 6 ways
P = 6/36 = 1/6
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19 Apr 2008 20:48:32 IST
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the ans is a since there are 6 ways of B to get more than 9 .n out of 36 possibilities the probability is 6/36 =1/6
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20 Apr 2008 12:22:34 IST
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1/6
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20 Apr 2008 12:24:55 IST
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srry its (5,5) &(6,6) 5,6 , 6,5 ......... hence 4/36
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