WHAT IS THE PROBABILITY THAT A NO. CHOSEN AT RANDOM FROM THE SET OF NATURAL NO.S CONTAINS THE NO. "7"?



SET OF NATURAL NO.S = 1,2,3,4,5,6, ... infinity



do tell me on what logic you get the answer... pls explain that...

how can be required no be 1

any1 bond who cn solve it

probability of occuring all the digits is same.

hence 10x=1[x=probability of occuring 1,2,3,4,..9,0)

so the ans is 1/10

rate me if its correct

1/10 is incorrect answer

dere r infinitely many natural no:s

d probability of occurence of 7 will be                      1/infinity=0

d probability is 0,so it proves to be an impossible event

pls rate if my answer is correct

Though the numbers which contain 7 are in good number,there are too less when compared to the set of natural no.s,So the probability tends to 0 acc to me.

but though 1/infinity is nearly equal 2 zero but not 0 so i think the answer might b 1/10