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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Probability, Geometry
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preetirocks (0)

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1.A fair coin is tossed repeatedly, if tail appears on first toss, then the probability of getting head on the fifth toss is??
2. Equation of pair of lines passing through (2,1) and perpendicular to 6x*+17xy+12y*=0
3. If focus and vertex of parabola are (0,2) and (0,4) respectively, then its equation is??
    
eragon007 (156)

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1)--as the coin is a fair one its probability of getting a head  even after infinite turns  will be 1/2, hence ans is 1/2

2)substitute x=x-2
                  y=y-1
in the eqn of straight lines

3)focus=0,2
  vertex = 0,4    => a = 2
 the general eqn for p'bola is

(y-y')=4a(x-x')
y'=2   x'=0
hence equation is
(y-2)=-8x(as the p'bola opens in the 2nd quadrant)
 

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raulrag009 (1223)

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Q2
 
Here
 
6x^{2}+17xy+12y^{2}=0\\\\
(3x+4y)(2x+3y)=0\\\\
 
Thus  

(3x+4y)=0\\\\(2x+3y)=0\\\\
are the two lines.
 
eqn of perpendicular lines is given by
 
4x-3y+\alpha=0\\\\
3x-2y+\mu=0\\\\
where \;\alpha\;and\;\mu\;are\;constants
 
since they pass through (2,1)
(2,1) should surely satisfy them
 
\alpha=-5\\\\
\mu=-4
 
 
thus eqn of pair of lines is
 
(4x-3y-5)(3x-2y-4)=0\\\\
12x^{2}-9xy-31x+14y+6y^{2}+20=0
 
 
forgive me for calculation mistakes
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