Q.A team of eight couples attended a lucky draw in which four persons are picked up for a prize. Then the probability that there is atleast one couple is ?
to find probability that no couple picks up the prize... first chosen in 16 ways next in 14 ways(avoiding him and partner) next in 12 ways and last in 10 ways
so no of ways is 16*14*12*10
total no of ways for choosing=16*15*14*13 so P=16*14*12*10/16*15*14*13 =24/39 so required P=1-P'=15/39
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