IIT JEE , AIEEE Forum - Mathematics , Algebra

Taara

pg 582 eg 37

why is p(A|B1) = 0.9 *0.9. shdn't it be just 0.9??

pg 584 14 and 13. how shd u do??

pls help me.

sandeepramesh

can you post the questions plz? I doubt if half the people here would have their text books with them Razz

sillyme1

The Question says.....

...the machine produces 2 acceptable items. hence the probability 0.9 for each. (bcos A is the event that the machine produces two acceptable items)

supralara

just now bothered to check the cbse book

yes it shld be just 0.9 only

the 13 th one is staight bayes thrm

the 14 th one is very simple

just list out the cases

cases no of posibilities

all four zeros 1

i one and three zeros 4!/ 3!=4

2 ones and two zeros 4!/ 2! 2!=6

three one sand one zero 4 possibilties again

all four ones 1 again

therefore toral cases=16

no of fav cases for mod to exist

1 0 or 1 0 or 1 1

0 1 1 1 0 1

therefore no of fav cases=3

hence 3/16

Taara

@supralara

pls explain how u got the no of posibilities