ans is 9/5
probability that a test is conducted on any one of the days that the student is absent = 4/5*1/5 +1/5*4/5-----------(1)
probabability that a test is held on both the days = 1/5*1/5-------(2)
therefore probability that the student will miss ATLEAST one test isgiven from (1) and (2)....
= 4/5*1/5 +1/5*4/5 +1/5*1/5 = 9/5
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