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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Jan 2008 14:25:19 IST
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Q. The odds that a book will be reviewed favorably by three independent critics are 5 to 2, 4 to 3 and 3 to 4 respectively.What is the probability that of three reviews a majority will be favorable?
please give a detailed solution and a generalised approach to solve this type of problems.
salutes assured!!
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it is not important where u stand, but in which direction u are moving |
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26 Jan 2008 14:35:05 IST
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prob= 3 favour + 2 favour = 5.4.3 /7^3 + 5/7 .4/7 .4/7 + 5/7 .3/7 . 3/7 + 2/7 . 4/7 . 3/7 = 60 + 80 + 45 + 24 / 7^3 = 209 / 343
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26 Jan 2008 14:36:14 IST
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do u knw the answer..........i need to check?
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" the only thing thats always constant in this world , is change itself.....
so it is better to adapt to the situation or life makes you adapt to it (painfully)..."
- Kundan a.k.a Juan dankh......
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26 Jan 2008 14:38:46 IST
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@ Richard
sir is it detailed??
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26 Jan 2008 14:39:50 IST
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The procedure is simple . 2 favour means two critics have reviewed it favourably & the other has not . So there arises 3 possible cases . ( expressions are self - explanatory )
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26 Jan 2008 14:41:00 IST
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answer is correct and i rated u for that.
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it is not important where u stand, but in which direction u are moving |
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26 Jan 2008 14:42:14 IST
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feynmann is correct 5/7*4/7*3/7 implies all 3 are favorable 5/7*4/7(1-3/7) implies A and B agree,C disagrees 5/7*3/7(1-4/7) implies A and C agree, B does not 4/7*3/7*(1-5/7) implies B and C agree,A disagrees adding these three cases we get the probablity
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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this question was already put up.......plz have a look at this to get a detailed explanation!!!!!!!!!!!!!! http://www.goiit.com/posts/list/algebra-probability-33409.htm
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