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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jan 2008 19:48:11 IST
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A pair of fair dice is thrown. What is the probability that the sum is 10 or greater if 5 appears on the first dice ?
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3 Jan 2008 22:11:09 IST
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Hey, the possibilities: (5,5),(5,6),(6,5),(6,4),(4,6)... given 5 on the start throw..... hence P=2/5.
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GIVE LIFE THE BEST....srini...
DO OR DIE, OR BETTER NEVER TRY!!
I dont want to be the most intelligent among the ten.i pray the other nine RE fools!???!!!!!!
it doesn't matter if you win... whats important to me is i win!!!!!!!! |
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4 Jan 2008 09:42:50 IST
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if 5 is fixed on the first die the the second dice can have 5 or 6 out of 6 chances..so probability is 2/6 = 1/3 but if the die on which the number 5 is fixed also has chance to vary then 1st die 2nd die 5 5 5 6 6 5 5 5 now the probability is 1* 2 + 2 *1/ 6 = 2/3
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Bad news is that time always flies,
Good news is that u r the pilot.
yesterday is history,
tomorrow is a mystery,
today is a gift and that is why it's called "the present". |
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4 Jan 2008 18:25:14 IST
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WE want that 5 should appear on first dice and sum should be equal
or greater than 10
then no. of favorable cases are = {(5,6),(5,5)}
total no. of cases for two dice=36
therefore probability = 2/36.= 1/18.
AM I RIGHT?????
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IMPOSSIBLES ARE OFTEN UNTRIED... |
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