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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 02:13:43 IST
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an unbiased die with faces marked 1 2 3 4 5 6 is rolled four times out of four face vaules obtained probality that min face value is not less than 2 and max is not grtr than 5 is
16/81
1//81
80/81
65/81
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16 Apr 2007 04:42:51 IST
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No. of ways in which 2,3,4,5 comes = 4
Total no. of ways (i.e. 1,2,3,4,5,6 comes) = 6
Hence probability of getting 2,3,4,5 = 4/6 = 2/3
Since the die is rolled 4 times :
Required probability = (2/3)(2/3)(2/3)(2/3) = 16/81
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 2 points
(with 0 
in 1 votes ) [?]
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