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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Probabilty question
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Sushmi (84)

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If 3 squares are selected at random from a chessboard,

then the probability that they form the letter L is :

a.)196 / 64 C 3                          b.) 49 / 64 C 3


c.)36 / 64 C 3                            d.) 98 / 64 C 3   


This is a good one i think!

    
computer001 (1847)

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edited:
will post in a couple of sec

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akhil_o (2709)

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Just count all the L shapes possible...
now in a 2x2 square there are 4 L shapes
so to count all 2x2 squares
consider row of 8 squares
so to choose 2 consecutive squares, 7 ways
similarly vertically 7 ways

so 7*7=49 total 2x2 boxes
so
49*4=196 total Ls
so P=196/64C3

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computer001 (1847)

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yeah a) only

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computer001 (1847)

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but i edited initially cuz there can be bigger L formations also...
but then i saw max itself is 198 only

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akhil_o (2709)

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i think the qn implies only 3 squares with 2 common sides joined to form Ls

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computer001 (1847)

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akhil wat do u say?
wat abt bigger L formations??
it comes down to wat u mean by an L actually

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computer001 (1847)

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thts wat i thot initially
n got a...but edited cuz v can also have more na?
lik 5 sq etc ths also a symmetric L...
but well i was stupid...maximum itself is 198 only...

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computer001 (1847)

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neway considerin L as a shape in which the 2 legs r equal in length how many r possible...
an extension of prev question

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akhil_o (2709)

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it should be quite easy...
just select one row,
select 2 in that, and in one of the columns select the next square

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akhil_o (2709)

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Ur answer would be

8C1*8C2*2C1*7/64C3

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computer001 (1847)

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its quite direct lik u said
its st away 49*64
 wid each sq as the joint of the L( i mean the turning pt) i can make 49 sq(as v have7*7)
64 such joints possible
so 64*49

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Sushmi (84)

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 Good work & nice discussion......u r correct Gokul I should have mentioned that.
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computer001 (1847)

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akhil, wat say?
@ sushmi: thts quite easy too.. i mean all the Ls
refer akhil's post and my prev post

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Sushmi (84)

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Yeah it was easy.....i found this quesn nearby and posted it as u wanted more quesns.
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