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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 May 2008 07:42:40 IST
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My sock drawer contains 6 black socks, 4 blue socks and 5 brown socks. On a dark winter morning, I randomly select two of these socks to wear. Find the chance that they are a matching pair, i.e., they have the same color.
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8 May 2008 12:28:22 IST
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for dis
either both the socks shud be ....brown or blk or blue
probablity=6/15)x(5/14)+(4/15)(3/14)+(5/15)(4/14)
=12/35
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even a stopped clock is right twice a day |
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8 May 2008 12:31:14 IST
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is the answer 31/105
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8 May 2008 12:52:28 IST
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Number of ways of choosing matching socks = 6C2+ 4C2 + 5C2=31
Total no of ways of selecting a pair of socks = 15C2=105
so probabiltiy of selecting matching pair = 31/105
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8 May 2008 12:58:06 IST
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kya bakwas question hai,, don get hurt yaar!!
No doubts its that selection process,, no order considering....
selecting matching socks goes by 6C2+ 4C2 + 5C2
and total ways by 15C2..
so i think ashish_banga has done same thing.
answer is 31/105
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But Jack of few!! |
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