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Ask iit jee aieee pet cbse icse state board experts Expert Question: probablity problem
Forum Index -> Algebra like the article? email it to a friend.  
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nilesh (7)

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Olaaa!! Perrrfect answer. 1  [2 rates]

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sir,please give me the sol
Q) A horizontal flat square board 6 inches wide is ruled with a grid of fine lines, 2 inches apart and has a vertical rim like a carom board, all round the edges. If a coin of diameter 2/3 inches is tossed on to the board. What is the probability that it rests without crossing a line?
(A) 0.5625
(B) 0.6525
(C) 0.6255
(D) 0.5562
 

hogwarts dropout!
    
puneet (3531)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 615  bad job dude!! I dont approve of this answer! 2  [847 rates]

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Refer to this figure to understand the answer of the problem.
 
The black area corresponds to the area in which the center of the coin cannot lie. The center of coin cannot lie on either side of the line till a distance of 1/3 inches as otherwise the line will be crossed.
Also since there is a vertical rim like carrom board so the center cannot lie within 1/3 inch from the boundary.
 
So we now calculate the area in which center can lie ..
 
This area comes out to be 3*(2-2/3)*3*(2-2/3) = 16.
 
Now the area in which the center can lie for all possible cases is (6-2/3)*(6-2/3)
 
Note that the area near the walls is not included because the center cannot lie within 1/3 inches of the walls.
 
Thus the probability that the lines will not be touched is
                                         
                                           16 / (6-2/3)*(6-2/3) = 0.5625
 
cheers

Puneet Agrawal
IIT Delhi
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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