IIT JEE , AIEEE Forum - Mathematics , Algebra

heman

3 students {A,B,C} takes the quiz together and offers a solution upon which majority of the 3 agrees . probablity of A solving the puzzle correctly is p . probablity of B solving the puzle is also p . C is a dumb student who randomly supports either A or B . There is one more student D , whose probablity of solving the puzzle is once again p , out of the 3 member team {A,B,C} and one member team {D} which one is more likely to solve the puzzle correctly .

Betu

it needs to be clarified the probability of c supporting A or B and whether solution offered by {A,B,C} needs to be supported by all three .

if C rarely supports A or B , then how this team offers solution

heman

c does not suports rarely c supports randomly......prob of c supprort a is = prob. of c support b i think i.e 0.5.....

coool_shetty

first tell me whether the answer is that the probabilities are same or not??
if yes , i will give the logic..

coool_shetty

for 2nd team as expected , the probability of D getting it rite is "p"

now for 1st team...
case 1: A and B get it right ...
     p(case 1)= p.p(0.5+0.5)     .......{0.5 for supporting and similarly for not supporting too in the other case ....in any case note that majority is already there..)

case 2:   A gets it right , B wrong and C gets it right
   p(case 2)=   p.(1-p).0.5       ....(probab of B getting it wrong is 1-p )

case 3:   B gets it right and A gets it wrong and C gets it right
    p(case 3)= same as above.....

adding all of them u get sum as p itself ...so the probabilities are same...

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