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rishipratimm (501)

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a,b,c are non zero numbers
az2 + bz + c + i = 0 has purely imaginary roots...
then find a. 

"Many of the things you can count,dont count....
Many of the things you cant count,really do count...."-Albert Einstein

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1ST YEAR,ELECTRONICS AND COMMUNICATIONS
    
lokeshsardana (692)

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Gentleman! Ur statement is wrong.

As u hav mentioned that roots r purely imag. & we know that imaginary roots always occurs in conj. sys.
So, roots must be of type ki and -ki
where k is any real no.
so, sum of roots is 0.
Hence b=0.
But u hav mentioned that a,b,c r non zero nos.

LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.


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hsbhatt (5581)

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he didnt say that a,b and c are real numbers themselves

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lokeshsardana (692)

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Aur maine kab kaha ki a,b,c real hai.
Infact , to satisfy above conditions b must be =0
and out of a and c, atleast one must be imaginary...
U can check..

LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.


Happiness can be found, even in the darkest of times, if one only remembers to turn on the light.
Albus Dumbledore
Harry Potter and the Prisoner of Azkaban movie


There are only two ways to live your life. One is as though nothing is a miracle. The other is as though everything is a miracle.
-- Albert Einstein

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anchitsaini (4377)

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actually
lokeshsardana
you have first assumed them to be real and then yourself proved that they are imaginary and not real

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hsbhatt (5581)

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@lokesh: non-real roots come in conjugate pairs when the coeffs are all real. If a,b and c are not given to be real then you cannot assume the roots to be conjugates. 

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anchitsaini (4377)

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hsbhatt sir ,lokesh first assumed that(which is certainly a wrong assumption) but if you see the last line he himself says
"Hence b=0.
But u hav mentioned that a,b,c r non zero nos."
therefore he realised his assumption is wrong

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